If two resistors of 6 Ω and 3 Ω are connected in series, what is the total resistance?

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Multiple Choice

If two resistors of 6 Ω and 3 Ω are connected in series, what is the total resistance?

Explanation:
In series, resistors add: the same current flows through each component, so the total opposition to current is the sum of the individual resistances. Here, 6 Ω plus 3 Ω gives 9 Ω, so the total resistance is 9 Ω. If they were arranged in parallel, the total would be less than either resistor and would use a reciprocal sum instead.

In series, resistors add: the same current flows through each component, so the total opposition to current is the sum of the individual resistances. Here, 6 Ω plus 3 Ω gives 9 Ω, so the total resistance is 9 Ω. If they were arranged in parallel, the total would be less than either resistor and would use a reciprocal sum instead.

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