If voltage doubles across a resistor while resistance stays the same, how does current change?

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Multiple Choice

If voltage doubles across a resistor while resistance stays the same, how does current change?

Explanation:
Current through a resistor with fixed resistance follows Ohm’s law: I = V / R. If you double the voltage while keeping the resistance the same, the current doubles as well because the same opposition to flow is now driven by twice the voltage. For example, with R = 5 Ω, V = 10 V gives I = 2 A; increasing V to 20 V gives I = 4 A. So the current increases by a factor of two. It wouldn’t quadruple, stay the same, or drop to zero since the relationship between voltage and current is linear when resistance is constant.

Current through a resistor with fixed resistance follows Ohm’s law: I = V / R. If you double the voltage while keeping the resistance the same, the current doubles as well because the same opposition to flow is now driven by twice the voltage. For example, with R = 5 Ω, V = 10 V gives I = 2 A; increasing V to 20 V gives I = 4 A. So the current increases by a factor of two. It wouldn’t quadruple, stay the same, or drop to zero since the relationship between voltage and current is linear when resistance is constant.

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