Which color code represents a 1 kΩ resistor with ±5% tolerance in a 4-band code?

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Multiple Choice

Which color code represents a 1 kΩ resistor with ±5% tolerance in a 4-band code?

Explanation:
In a 4-band resistor code, the first two colors are the digits of the resistance, the third color is the multiplier (power of ten), and the fourth color is the tolerance. For 1 kΩ with ±5% tolerance, you need 1 and 0 as the digits, so brown = 1 and black = 0. The multiplier must be 100 (10^2), which is red. The tolerance of ±5% is gold. Put together, the sequence is brown, black, red, gold. This yields 10 × 100 = 1000 Ω with 5% tolerance. Other sequences would produce different values, such as 100 Ω (brown, black, brown, gold) or 6.8 kΩ (blue, gray, red, gold).

In a 4-band resistor code, the first two colors are the digits of the resistance, the third color is the multiplier (power of ten), and the fourth color is the tolerance. For 1 kΩ with ±5% tolerance, you need 1 and 0 as the digits, so brown = 1 and black = 0. The multiplier must be 100 (10^2), which is red. The tolerance of ±5% is gold. Put together, the sequence is brown, black, red, gold. This yields 10 × 100 = 1000 Ω with 5% tolerance. Other sequences would produce different values, such as 100 Ω (brown, black, brown, gold) or 6.8 kΩ (blue, gray, red, gold).

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